Optimal. Leaf size=143 \[ -\frac{e^{2 a} 2^{-\frac{m+2 n+1}{n}} (e x)^{m+1} \left (-b x^n\right )^{-\frac{m+1}{n}} \text{Gamma}\left (\frac{m+1}{n},-2 b x^n\right )}{e n}-\frac{e^{-2 a} 2^{-\frac{m+2 n+1}{n}} (e x)^{m+1} \left (b x^n\right )^{-\frac{m+1}{n}} \text{Gamma}\left (\frac{m+1}{n},2 b x^n\right )}{e n}-\frac{(e x)^{m+1}}{2 e (m+1)} \]
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Rubi [A] time = 0.174381, antiderivative size = 143, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.188, Rules used = {5362, 5361, 2218} \[ -\frac{e^{2 a} 2^{-\frac{m+2 n+1}{n}} (e x)^{m+1} \left (-b x^n\right )^{-\frac{m+1}{n}} \text{Gamma}\left (\frac{m+1}{n},-2 b x^n\right )}{e n}-\frac{e^{-2 a} 2^{-\frac{m+2 n+1}{n}} (e x)^{m+1} \left (b x^n\right )^{-\frac{m+1}{n}} \text{Gamma}\left (\frac{m+1}{n},2 b x^n\right )}{e n}-\frac{(e x)^{m+1}}{2 e (m+1)} \]
Antiderivative was successfully verified.
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Rule 5362
Rule 5361
Rule 2218
Rubi steps
\begin{align*} \int (e x)^m \sinh ^2\left (a+b x^n\right ) \, dx &=\int \left (-\frac{1}{2} (e x)^m+\frac{1}{2} (e x)^m \cosh \left (2 a+2 b x^n\right )\right ) \, dx\\ &=-\frac{(e x)^{1+m}}{2 e (1+m)}+\frac{1}{2} \int (e x)^m \cosh \left (2 a+2 b x^n\right ) \, dx\\ &=-\frac{(e x)^{1+m}}{2 e (1+m)}+\frac{1}{4} \int e^{-2 a-2 b x^n} (e x)^m \, dx+\frac{1}{4} \int e^{2 a+2 b x^n} (e x)^m \, dx\\ &=-\frac{(e x)^{1+m}}{2 e (1+m)}-\frac{2^{-\frac{1+m+2 n}{n}} e^{2 a} (e x)^{1+m} \left (-b x^n\right )^{-\frac{1+m}{n}} \Gamma \left (\frac{1+m}{n},-2 b x^n\right )}{e n}-\frac{2^{-\frac{1+m+2 n}{n}} e^{-2 a} (e x)^{1+m} \left (b x^n\right )^{-\frac{1+m}{n}} \Gamma \left (\frac{1+m}{n},2 b x^n\right )}{e n}\\ \end{align*}
Mathematica [A] time = 1.90741, size = 117, normalized size = 0.82 \[ -\frac{x (e x)^m \left (e^{2 a} (m+1) 2^{-\frac{m+1}{n}} \left (-b x^n\right )^{-\frac{m+1}{n}} \text{Gamma}\left (\frac{m+1}{n},-2 b x^n\right )+e^{-2 a} (m+1) 2^{-\frac{m+1}{n}} \left (b x^n\right )^{-\frac{m+1}{n}} \text{Gamma}\left (\frac{m+1}{n},2 b x^n\right )+2 n\right )}{4 (m+1) n} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.207, size = 0, normalized size = 0. \begin{align*} \int \left ( ex \right ) ^{m} \left ( \sinh \left ( a+b{x}^{n} \right ) \right ) ^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\left (e x\right )^{m} \sinh \left (b x^{n} + a\right )^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (e x\right )^{m} \sinh ^{2}{\left (a + b x^{n} \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (e x\right )^{m} \sinh \left (b x^{n} + a\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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